Selesai Masalah Matematik

micha · Post time 14-2-2008 02:52 PM

Originally posted by Atomic_Omnikid at 2-2-2008 02:09 PM

0000 + 000 + 00 + 0 = 0
8888 + 888 + 88 + 8 = 9872

tAHNIAH.....

BETUL!!!!!!!

HEHEHEHEHEHEHE.........

daigo_tiga · Post time 16-2-2008 01:51 PM

x de soalan lain ke micha?

micha · Post time 17-2-2008 11:19 AM

nnt micha pk soklan dulu k..... ader bnyk nih.....huhuhuhu....

EAStudent · Post time 17-2-2008 02:25 PM

cepat ar..
aku tengah bermint nak jwab nie..\

daigo_tiga · Post time 18-2-2008 02:47 PM

cepat...cepat...

he...he....

Atomic_Omnikid · Post time 18-2-2008 11:35 PM

Originally posted by micha at 14-2-2008 14:52

tAHNIAH.....

BETUL!!!!!!!

HEHEHEHEHEHEHE.........

Tengkiu...

macam-macam..

testas · Post time 27-2-2008 05:55 PM

cik micha ni manja laaaa

micha · Post time 28-2-2008 11:20 AM

i manja ala2 ganas.... hahahaha....

micha · Post time 28-2-2008 11:24 AM

u all soklan seterusnye....

expand this expression ( ( 2xy + x*)*)*, which * = square.... cepat u all congak je

ben_G · Post time 28-2-2008 05:01 PM

Try test tengok..lame xwat math ni..

Jawapan : 16 x*4 y*4 + 20 x*5 y*3 + 12 x*6 y*2 + 8 x*7 y + x*8

info:
x*4=x to the power of 4

tol ke salah?

Atomic_Omnikid · Post time 28-2-2008 10:15 PM

( ( 2xy + x*)*)*
=((2 x y + x^2)^2)^2
=(2 x y + x^2)^4
=16 x^4 y^4 + 24 y^2 x^6 + 32 y^3 x^5 + 8 y x^7 + x^8 ..

kena guna binomial expansion nie..

[ Last edited by Atomic_Omnikid at 28-2-2008 10:16 PM ]

nafham · Post time 29-2-2008 12:09 AM

micha · Post time 3-3-2008 03:17 PM

Originally posted by thessailly at 29-2-2008 03:28 AM

( ( 2 x y + x * ) * ) *

betul tak?
(kena kena expand jauh lagi sikit?)...hurm...

yessssss.... pandainye....

lg jauh lg tepat....

hahahaha.... congrates

Atomic_Omnikid · Post time 3-3-2008 07:27 PM

Originally posted by micha at 3-3-2008 15:17

yessssss.... pandainye....

lg jauh lg tepat....

hahahaha.... congrates

micha · Post time 3-3-2008 07:39 PM

gurau je. yg srius pnye, jawapan nafham tu betul....

jawapan u pn betul gak.... huhuhuhu. tahniah....

micha · Post time 19-3-2008 11:09 AM

soalan baruuuuuuu.....

2^x = 3^y = 6^z.... ( ^ = to the power ) , find value of x, y, z.....

test1234 · Post time 10-4-2008 12:29 AM

x = 0
y = 0
z = 0

sbb sume same dgn 1.. tul ke??

micha · Post time 12-4-2008 02:48 AM

yes. great..... congrates

test1234 · Post time 14-4-2008 03:13 PM

takdo ke soklan baru?? huhu..

micha · Post time 15-4-2008 05:06 AM

pakai equation sama,

2^x = 3^y = 6^z, express z in term of x n y

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